## USACO 2023 February Contest, Platinum

## Problem 1. Hungry Cow

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****Note: The time limit for this problem is 6s, three times the default. The
memory limit for this problem is 512MB, twice the default.****

Bessie is a hungry cow. Each day, for dinner, if there is a haybale in the barn, she will eat one haybale. Farmer John does not want Bessie to starve, so some days he sends a delivery of haybales, which arrive in the morning (before dinner). In particular, on day $d_i$, Farmer John sends a delivery of $b_i$ haybales ($1\leq d_i \leq 10^{14}$, $0\leq b_i \leq 10^9$).

Process $U$ ($1\le U\le 10^5$) updates as follows: Given a pair $(d, b)$, update the number of haybales arriving on day $d$ to $b$. After each update, output the sum of all days on which Bessie eats haybales modulo $10^9+7$.

#### INPUT FORMAT (input arrives from the terminal / stdin):

$U$, followed by $U$ lines containing the updates.#### OUTPUT FORMAT (print output to the terminal / stdout):

The sum after each update modulo $10^9+7$.#### SAMPLE INPUT:

3 4 3 1 5 1 2

#### SAMPLE OUTPUT:

15 36 18

Answers after each update:

4+5+6=15 1+2+3+4+5+6+7+8=36 1+2+4+5+6=18

#### SAMPLE INPUT:

9 1 89 30 7 101 26 1 24 5 1 60 4 5 10 101 0 1 200

#### SAMPLE OUTPUT:

4005 4656 7607 3482 3507 3753 4058 1107 24531

#### SCORING:

- Input 3: $U\le 5000$
- Inputs 4-10: Updates only increase the number of haybales arriving on day $d$.
- Inputs 11-22: No additional constraints.

Problem credits: Brandon Wang and Benjamin Qi