
USACO 2023 February Contest, Platinum
Problem 1. Hungry Cow
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**Note: The time limit for this problem is 6s, three times the default. The memory limit for this problem is 512MB, twice the default.**
Bessie is a hungry cow. Each day, for dinner, if there is a haybale in the barn, she will eat one haybale. Farmer John does not want Bessie to starve, so some days he sends a delivery of haybales, which arrive in the morning (before dinner). In particular, on day di, Farmer John sends a delivery of bi haybales (1≤di≤1014, 0≤bi≤109).
Process U (1≤U≤105) updates as follows: Given a pair (d,b), update the number of haybales arriving on day d to b. After each update, output the sum of all days on which Bessie eats haybales modulo 109+7.
INPUT FORMAT (input arrives from the terminal / stdin):
U, followed by U lines containing the updates.OUTPUT FORMAT (print output to the terminal / stdout):
The sum after each update modulo 109+7.SAMPLE INPUT:
3 4 3 1 5 1 2
SAMPLE OUTPUT:
15 36 18
Answers after each update:
4+5+6=15 1+2+3+4+5+6+7+8=36 1+2+4+5+6=18
SAMPLE INPUT:
9 1 89 30 7 101 26 1 24 5 1 60 4 5 10 101 0 1 200
SAMPLE OUTPUT:
4005 4656 7607 3482 3507 3753 4058 1107 24531
SCORING:
- Input 3: U≤5000
- Inputs 4-10: Updates only increase the number of haybales arriving on day d.
- Inputs 11-22: No additional constraints.
Problem credits: Brandon Wang and Benjamin Qi