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USACO 2023 February Contest, Platinum

Problem 1. Hungry Cow


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**Note: The time limit for this problem is 6s, three times the default. The memory limit for this problem is 512MB, twice the default.**

Bessie is a hungry cow. Each day, for dinner, if there is a haybale in the barn, she will eat one haybale. Farmer John does not want Bessie to starve, so some days he sends a delivery of haybales, which arrive in the morning (before dinner). In particular, on day di, Farmer John sends a delivery of bi haybales (1di1014, 0bi109).

Process U (1U105) updates as follows: Given a pair (d,b), update the number of haybales arriving on day d to b. After each update, output the sum of all days on which Bessie eats haybales modulo 109+7.

INPUT FORMAT (input arrives from the terminal / stdin):

U, followed by U lines containing the updates.

OUTPUT FORMAT (print output to the terminal / stdout):

The sum after each update modulo 109+7.

SAMPLE INPUT:

3
4 3
1 5
1 2

SAMPLE OUTPUT:

15
36
18

Answers after each update:

4+5+6=15
1+2+3+4+5+6+7+8=36
1+2+4+5+6=18

SAMPLE INPUT:

9
1 89
30 7
101 26
1 24
5 1
60 4
5 10
101 0
1 200

SAMPLE OUTPUT:

4005
4656
7607
3482
3507
3753
4058
1107
24531

SCORING:

  • Input 3: U5000
  • Inputs 4-10: Updates only increase the number of haybales arriving on day d.
  • Inputs 11-22: No additional constraints.

Problem credits: Brandon Wang and Benjamin Qi

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