(Analysis by Nick Wu)

Sort the haybales by location. Consider two haybales $i$ and $j$ such that Bessie can start somewhere between those haybales and break through all the haybales from $i+1$ to $j-1$, but she can't break haybale $i$ or haybale $j$.

It must be the case then that no haybale between $i$ and $j$ is strictly taller than those two. That motivates the following $O(N \log N)$ solution:

Sort the haybales in decreasing order of size. Consider having an empty road, and place the haybales in that order. When placing a haybale, look immediately to its left and to its right and see if you can break through either one of those haybales if you were inside that interval. Mark that interval as "trapped" if so.

This will be $O(N \log N)$ as long as you check to make sure that the interval isn't already marked as trapped.

Here is my code illustrating this process.

import java.io.*;
import java.util.*;
public class trappedG {
  public static void main(String[] args) throws IOException {
    BufferedReader br = new BufferedReader(new FileReader("trapped.in"));
    PrintWriter pw = new PrintWriter(new BufferedWriter(new FileWriter("trapped.out")));
    int n = Integer.parseInt(br.readLine());
    Haybale[] bales = new Haybale[n];
    for(int i = 0; i < n; i++) {
      StringTokenizer st = new StringTokenizer(br.readLine());
      int size = Integer.parseInt(st.nextToken());
      int position = Integer.parseInt(st.nextToken());
      bales[i] = new Haybale(size, position);
    }
    Arrays.sort(bales, new PosComp());
    int[] locations = new int[n];
    Map<Integer, Integer> map = new HashMap<Integer, Integer>();
    Map<Integer, Integer> locToSize = new HashMap<Integer, Integer>();
    for(int i = 0; i < n; i++) {
      locations[i] = bales[i].position;
      map.put(locations[i], i);
      locToSize.put(bales[i].position, bales[i].size);
    }
    Arrays.sort(bales, new SizeComp());
    TreeSet<Integer> seen = new TreeSet<Integer>();
    int ans = 0;
    boolean[] covered = new boolean[n-1];
    for(Haybale out: bales) {
      int index = map.get(out.position);
      if(seen.size() > 0 && seen.last() > index) {
        int higherIndex = seen.higher(index);
        int distance = locations[higherIndex] - locations[index];
        if(distance <= locToSize.get(locations[higherIndex]) && distance <= out.size) {
          int l = index;
          int r = higherIndex;
          if(!covered[l]) {
            for(int i = l; i < r; i++) {
              covered[i] = true;
            }
          }
        }
      }
      if(seen.size() > 0 && seen.first() < index) {
        int lowerIndex = seen.lower(index);
        int distance = locations[index] - locations[lowerIndex];
        if(distance <= locToSize.get(locations[lowerIndex]) && distance <= out.size) {
          int l = lowerIndex;
          int r = index;
          if(!covered[l]) {
            for(int i = l; i < r; i++) {
              covered[i] = true;
            }
          }
        }
      }
      seen.add(index);
    }
    for(int i = 0; i < covered.length; i++) {
      if(covered[i]) {
        ans += locations[i+1] - locations[i];
      }
    }
    pw.println(ans);
    pw.close();
  }
    
  static class Haybale {
    public int position, size;
    public Haybale(int sizeIn, int positionIn) {
      size = sizeIn;
      position = positionIn;
    }
  }

  static class PosComp implements Comparator<Haybale> {
    public int compare(Haybale a, Haybale b) {
      return a.position - b.position;
    }
  }
  
  static class SizeComp implements Comparator<Haybale> {
    public int compare(Haybale a, Haybale b) {
      return b.size - a.size;
    }
  }
  
}